48+2x^2=16

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Solution for 48+2x^2=16 equation: 



48+2x^2=16

We move all terms to the left:

48+2x^2-(16)=0

We add all the numbers together, and all the variables

2x^2+32=0

a = 2; b = 0; c = +32;
Δ = b2-4ac
Δ = 02-4·2·32
Δ = -256
Delta is less than zero, so there is no solution for the equation

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